Determination of the Fundamental Electronic Charge

ELECTROLOYSIS OF WATER DETERMINATION OF THE wakeless ELECTRONIC CHARGE PURPOSE The fundamental electronic weight down of wet depart be determined. A system of collecting the take ination of H2 and O2 utilize two inverted glass sights tubes and a 1-L beaker filled with body of body of water pull up stakes be setup. An electrolyte (H2SO4) will be added to water to make it an electrical conductor. A small amount of electricity will be applied to the water (roughly 400 mA) to oxidize the oxygen and reduce the hydrogen at the akin time. The molecular hydrogen and oxygen be adriftes produced will be trapped in the separated, inverted tubes so that their volumes can be measured.In comparing the volume of gases produced, applying Daltons Law and the Ideal Gas Equation along with the application of the stoichiometric ratio between the electron and the gases, the fundamental electronic charge will be determined. THEORY H+ ions will join together at the cathode (the negative electro de) to produce H Atoms, and the H atoms will join to form molecules of H2 gas. At the positive electrode (the anode), H20 molecules will decompose to replace the H+ ions lost and release O2 gas. The reactions appear below. H+(aq) + 2e- &8212> H2(g) Reduction (at the cathode) 2H20(l) &8212> 4H+(aq) + O2(g) + 4e-Oxidation (at the anode) The volume of H2 and O2 will be directly proportional to the time and current applied to the system. This will suffer the number of electrons consumed on a stoichiometric ratio as follows 1 H2(g) to 2 e-Reduction (at the cathode)(1) 1 O2(g) to 4 e-Oxidation (at the anode)(2) The moles of electrons can be expressed as a rearrangement of the Ideal Gas Equation Ne = PV/RT(3) Where P = ram in atm, V = volume in L, R = Gas ceaseless of 0. 08206 atm mol-1 K-1 and T = temperature in KelvinThe actual electronic charge of water will be calculated as follows e- = it/NeNx the stoichiometric ratio (1) or (2) above Where i = current in amps, t = time in sec onds, Ne = moles of electrons passing through the circuit from equation (3) and N = Avogadros number. The actual electronic charge will be compared to the theoretical charge of 1. 603&21510-19 Coulombs. 1. Convert height of the solution into mm Hg to get the hydrostatic jam (pressure due to the liquid left in the gas collection tube) height of solution x density of solution density of mercury 2. tmospheric pressure in the room hydrostatic pressure = Ptotal (total pressure exerted by the gas trapped in the gas collection tubes) 3. a)Ptotal (total pressure) = PH2 + PH20or Ptotal = PO2 + PH20 b) PH2 = Ptotal PH20 c)PH2 / 760 = Patm (Pressure) 4. Ne = PV/RT 5. e- = it/NeNx the stoichiometric ratio Run 1 Run1 Run 2 Run 2 (cathode) + (anode) (cathode) + (anode) organ pipe 2 Tube 1 Tube 2 Tube 1 H2 O2 H2 O2 Run Time in seconds 987. 13 987. 13 1102. 82 1102. 82 Average Current 0. 303 0. 303 0. 277 A Height of Solution Hsol mm 400. 325. 0 81. 5 314. 2 Volume of ga s produced Vgas (mL) 40. 10 19. 72 40. 10 19. 80 Vgas (L) 0. 04010 0. 01972 0. 04010 0. 01980 Temperature of solution C 24. 0 24. 0 25. 6 25. 6 Kelvin 297. 15 297. 15 298. 75 298. 75 dehydration pressure of water mm Hg 22. 377 22. 377 24. 617 24. 617 Atmospheric pressure Patm mm Hg 770. 50 770. 50 770. 50 770. 50 Patm 0. 94567 0. 95293 0. 97354 0. 95103 hhg hydrostatic pressure (mm Hg) 29. 41 23. 90 5. 99 23. 0 Ptotal (mm Hg) in the tube 741. 09 746. 60 764. 51 747. 40 PH2 (mm Hg) 718. 71 739. 89 PO2 (mm Hg) 724. 23 722. 78 moles gas n (rearranged Ideal Gas Equation) Ne = PV/RT 0. 001555 0. 0007707 0. 001592 0. 0007681 e- = it/NeN 3. 194E-19 6. 445E-19 3. 185E-19 6. 604E-19 stoichiometric ratio last 1. 597E-19 1. 611E-19 1. 593E-19 1. 651E-19 theoretical 1. 603E-19 1. 603E-19 1. 603E-19 1. 603E-19 Difference -6. 193E-22 8. 166E-22 -1. 028E-21 4. 801E-21 % Error -0. 4% 0. 5% -0. 6% 3. 0%